58 DOUBLE PRECISION :: A(*), L(*), U(*)
63 DOUBLE PRECISION :: SUM
81 sum = sum + l((i-1)*n + j) * u((j-1)*n + k)
83 u((i-1)*n + k) = a((i-1)*n + k) - sum
90 l((i-1)*n + i) = 1.0d0
94 sum = sum + l((k-1)*n + j) * u((j-1)*n + i)
98 IF (u((i-1)*n + i) .EQ. 0.0d0)
THEN
103 l((k-1)*n + i) = (a((k-1)*n + i) - sum) / u((i-1)*n + i)