58 DOUBLE PRECISION :: A(*), L(*), U(*)
63 DOUBLE PRECISION :: SUM
81 sum = sum + l((i-1)*n + k) * u((k-1)*n + j)
83 l((i-1)*n + j) = a((i-1)*n + j) - sum
90 u((j-1)*n + i) = 1.0d0
94 sum = sum + l((j-1)*n + k) * u((k-1)*n + i)
98 IF (l((j-1)*n + j) .EQ. 0.0d0)
THEN
103 u((j-1)*n + i) = (a((j-1)*n + i) - sum) / l((j-1)*n + j)